Problem
Balance following chemical equation
K2Cr2O7+HCl-> KCl+ CrCl3+H2O+ Cl2
Solution
Step 1
Write the chemical equation as follows.
A K2Cr2O7+B HCl->C KCl+D CrCl3+E H2O+F Cl2
A,B,C and D are number of K2Cr2O7,HCl,KCl,CrCl3 and H2O molecules participating in chemical reaction.
Step 2
For a balanced equation number of K,Cr,O,H and Cl atoms on left and right hand side should be equal
K --- 2A=C
Cr --- 2A=D
O --- 7A=E
H --- B=2E
Cl --- B=C+3D+2F
Step 3
Solve simultaneous equations described in step 2
B=14A
C=2A
D=2A
E=7A
F=3A
Step 4
Write balanced equation after cancelling A from left hand side and right hand side.
K2Cr2O7+14HCL->2KCL+2CrCl3+7H20+3ACl2
K2Cr2O7+14HCL->2KCL+2CrCl3+7H20+3ACl2
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